![Modular (Remainder) Arithmetic n = qk + r (for some k; r < k) eg 37 = (2)(17) + 3 Divisibility notation: 17 | n mod k = r 37 mod 17 = ppt download Modular (Remainder) Arithmetic n = qk + r (for some k; r < k) eg 37 = (2)(17) + 3 Divisibility notation: 17 | n mod k = r 37 mod 17 = ppt download](https://images.slideplayer.com/26/8780672/slides/slide_11.jpg)
Modular (Remainder) Arithmetic n = qk + r (for some k; r < k) eg 37 = (2)(17) + 3 Divisibility notation: 17 | n mod k = r 37 mod 17 = ppt download
![SOLVED: 1. (10 pts) Find the least residue of each of the following, in the given modulus. 10 = mod 5 (6)-4 = mod 13 c) 19 = mod 12 345 = mod 3 e) 475 = mod 10 78 = mod 13 -19 = mod 8 345 = mod 3 725 = mod 30 -28 = mod 4 SOLVED: 1. (10 pts) Find the least residue of each of the following, in the given modulus. 10 = mod 5 (6)-4 = mod 13 c) 19 = mod 12 345 = mod 3 e) 475 = mod 10 78 = mod 13 -19 = mod 8 345 = mod 3 725 = mod 30 -28 = mod 4](https://cdn.numerade.com/ask_previews/cd08932d-9bc1-4d28-b481-aee3c2eb3543_large.jpg)
SOLVED: 1. (10 pts) Find the least residue of each of the following, in the given modulus. 10 = mod 5 (6)-4 = mod 13 c) 19 = mod 12 345 = mod 3 e) 475 = mod 10 78 = mod 13 -19 = mod 8 345 = mod 3 725 = mod 30 -28 = mod 4
![modular arithmetic - What does $p≡3\mod4$ mean, and how do you find a prime matching this pattern? - Mathematics Stack Exchange modular arithmetic - What does $p≡3\mod4$ mean, and how do you find a prime matching this pattern? - Mathematics Stack Exchange](https://i.stack.imgur.com/wZE5S.png)
modular arithmetic - What does $p≡3\mod4$ mean, and how do you find a prime matching this pattern? - Mathematics Stack Exchange
![Java on Twitter: "Using Math.floorMod() to describe a modulo (or modulus) operation and % operator for the remainder operation. https://t.co/Tm1nkjPiUu https://t.co/NBLCFxcZ2K" / Twitter Java on Twitter: "Using Math.floorMod() to describe a modulo (or modulus) operation and % operator for the remainder operation. https://t.co/Tm1nkjPiUu https://t.co/NBLCFxcZ2K" / Twitter](https://pbs.twimg.com/media/ETPaqOpX0AI-Uv7.png)